Largest Rectangle in Some Region in the First Quadrant

Find the area of the largest rectangle that can be inscribed in the region bounded by the curve y=e^{-x}, the line x=0 and the positive x-axis.

Solution

Denote by x the point as shown in the figure. Then the rectangle inscribed in the region has dimensions x by e^{-x}. Thus, we need to maximize the area function

\displaystyle A(x)=xe^{-x}

To this end, we compute the function’s derivative:

A'(x)=-xe^{-x}+e^{-x}=e^{-x}\left(1-x\right)

We see that x=1 is the only critical point of the function.

We shall now use the first derivative test to show that the point where x=1 yields a maximum value. Note that e^{-x} is always positive hence the sign of \displaystyle A' depends only on the sign of the factor 1-x. It is now apparent that A' is positive if x<1 and negative if x>1. By the first derivative test, the point x=1 gives a relative maximum value.

The result also follows immediately from the second derivative test. Indeed, A''(x)=-e^{-x}\left(2-x\right) and clearly, A''(1)<0.

We therefore conclude that the largest rectangle that can be inscribed in the region has dimensions 1 and \displaystyle \frac{1}{e} and its area is \displaystyle \frac{1}{e} square units.

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